143123600556341 has 2 divisors, whose sum is σ = 143123600556342. Its totient is φ = 143123600556340.

The previous prime is 143123600556259. The next prime is 143123600556359. The reversal of 143123600556341 is 143655006321341.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 141409912728100 + 1713687828241 = 11891590^2 + 1309079^2 .

It is a cyclic number.

It is not a de Polignac number, because 143123600556341 - 2¹⁴ = 143123600539957 is a prime.

It is a super-2 number, since 2×143123600556341² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 143123600556292 and 143123600556301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143123603556341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71561800278170 + 71561800278171.

It is an arithmetic number, because the mean of its divisors is an integer number (71561800278171).

Almost surely, 2^{143123600556341} is an apocalyptic number.

It is an amenable number.

143123600556341 is a deficient number, since it is larger than the sum of its proper divisors (1).

143123600556341 is an equidigital number, since it uses as much as digits as its factorization.

143123600556341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 777600, while the sum is 44.

Adding to 143123600556341 its reverse (143655006321341), we get a palindrome (286778606877682).

The spelling of 143123600556341 in words is "one hundred forty-three trillion, one hundred twenty-three billion, six hundred million, five hundred fifty-six thousand, three hundred forty-one".