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143411000415 = 359560733361
BaseRepresentation
bin1000010110001111110…
…1100011010001011111
3111201011120002122122220
42011203331203101133
54322201204003130
6145514311240423
713234600250634
oct2054375432137
9451146078586
10143411000415
1155902853251
1223964079113
13106a6469b37
146d2666018b
153ae53ed410
hex2163f6345f

143411000415 has 8 divisors (see below), whose sum is σ = 229457600688. Its totient is φ = 76485866880.

The previous prime is 143411000399. The next prime is 143411000443. The reversal of 143411000415 is 514000114341.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 143411000415 - 24 = 143411000399 is a prime.

It is a super-2 number, since 2×1434110004152 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4780366666 + ... + 4780366695.

It is an arithmetic number, because the mean of its divisors is an integer number (28682200086).

Almost surely, 2143411000415 is an apocalyptic number.

143411000415 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

143411000415 is a deficient number, since it is larger than the sum of its proper divisors (86046600273).

143411000415 is an equidigital number, since it uses as much as digits as its factorization.

143411000415 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9560733369.

The product of its (nonzero) digits is 960, while the sum is 24.

Adding to 143411000415 its reverse (514000114341), we get a palindrome (657411114756).

The spelling of 143411000415 in words is "one hundred forty-three billion, four hundred eleven million, four hundred fifteen", and thus it is an aban number.

Divisors: 1 3 5 15 9560733361 28682200083 47803666805 143411000415