Base | Representation |
---|---|
bin | 1101000011100001000001… |
… | …0000011011001011101111 |
3 | 1212211020022122221110102110 |
4 | 3100320100100123023233 |
5 | 3340134100140204320 |
6 | 50310054445055103 |
7 | 3011021553103563 |
oct | 320702020331357 |
9 | 55736278843373 |
10 | 14354053444335 |
11 | 4634579a61730 |
12 | 1739ab3557493 |
13 | 801773537037 |
14 | 378a503a76a3 |
15 | 19d5adc325e0 |
hex | d0e1041b2ef |
14354053444335 has 64 divisors (see below), whose sum is σ = 25270834176000. Its totient is φ = 6899590800000.
The previous prime is 14354053444309. The next prime is 14354053444391. The reversal of 14354053444335 is 53344435045341.
It is a happy number.
It is not a de Polignac number, because 14354053444335 - 28 = 14354053444079 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 11855310 + ... + 13009860.
It is an arithmetic number, because the mean of its divisors is an integer number (394856784000).
Almost surely, 214354053444335 is an apocalyptic number.
14354053444335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
14354053444335 is a deficient number, since it is larger than the sum of its proper divisors (10916780731665).
14354053444335 is a wasteful number, since it uses less digits than its factorization.
14354053444335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1155220.
The product of its (nonzero) digits is 10368000, while the sum is 48.
Adding to 14354053444335 its reverse (53344435045341), we get a palindrome (67698488489676).
The spelling of 14354053444335 in words is "fourteen trillion, three hundred fifty-four billion, fifty-three million, four hundred forty-four thousand, three hundred thirty-five".
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