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144034223035 = 517299677663
BaseRepresentation
bin1000011000100100011…
…0111101001110111011
3111202202222210122101011
42012021012331032323
54324440230114120
6150100213134351
713256205460333
oct2061106751673
9452688718334
10144034223035
11560a262266a
1223ab892a3b7
1310775606911
146d853300c3
153b2eea6c5a
hex21891bd3bb

144034223035 has 12 divisors (see below), whose sum is σ = 183606257088. Its totient is φ = 108449296256.

The previous prime is 144034223017. The next prime is 144034223083. The reversal of 144034223035 is 530322430441.

It is a happy number.

It is not a de Polignac number, because 144034223035 - 233 = 135444288443 is a prime.

It is a super-2 number, since 2×1440342230352 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 144034222988 and 144034223006.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 49837387 + ... + 49840276.

It is an arithmetic number, because the mean of its divisors is an integer number (15300521424).

Almost surely, 2144034223035 is an apocalyptic number.

144034223035 is a deficient number, since it is larger than the sum of its proper divisors (39572034053).

144034223035 is an equidigital number, since it uses as much as digits as its factorization.

144034223035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 99677702 (or 99677685 counting only the distinct ones).

The product of its (nonzero) digits is 34560, while the sum is 31.

Adding to 144034223035 its reverse (530322430441), we get a palindrome (674356653476).

The spelling of 144034223035 in words is "one hundred forty-four billion, thirty-four million, two hundred twenty-three thousand, thirty-five".

Divisors: 1 5 17 85 289 1445 99677663 498388315 1694520271 8472601355 28806844607 144034223035