144110130041020 has 192 divisors, whose sum is σ = 359550096998400. Its totient is φ = 47828735677440.

The previous prime is 144110130040997. The next prime is 144110130041147. The reversal of 144110130041020 is 20140031011441.

It is a super-3 number, since 3×144110130041020³ (a number of 43 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (22).

It is a junction number, because it is equal to n+sod(n) for n = 144110130040982 and 144110130041000.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 148840917 + ... + 149806003.

It is an arithmetic number, because the mean of its divisors is an integer number (1872656755200).

Almost surely, 2^{144110130041020} is an apocalyptic number.

144110130041020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 144110130041020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (179775048499200).

144110130041020 is an abundant number, since it is smaller than the sum of its proper divisors (215439966957380).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

144110130041020 is a wasteful number, since it uses less digits than its factorization.

144110130041020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 965708 (or 965706 counting only the distinct ones).

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 144110130041020 its reverse (20140031011441), we get a palindrome (164250161052461).

The spelling of 144110130041020 in words is "one hundred forty-four trillion, one hundred ten billion, one hundred thirty million, forty-one thousand, twenty".