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14512211501 is a prime number
BaseRepresentation
bin11011000001111111…
…01100011000101101
31101110101021201122212
431200333230120231
5214210111232001
610400011020205
71022424522344
oct154077543055
941411251585
1014512211501
116177846327
12299013a665
1314a377b2c8
149b952ab5b
1559e0ae7bb
hex360fec62d

14512211501 has 2 divisors, whose sum is σ = 14512211502. Its totient is φ = 14512211500.

The previous prime is 14512211477. The next prime is 14512211503. The reversal of 14512211501 is 10511221541.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9618509476 + 4893702025 = 98074^2 + 69955^2 .

It is an emirp because it is prime and its reverse (10511221541) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14512211501 - 26 = 14512211437 is a prime.

Together with 14512211503, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14512211503) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7256105750 + 7256105751.

It is an arithmetic number, because the mean of its divisors is an integer number (7256105751).

Almost surely, 214512211501 is an apocalyptic number.

It is an amenable number.

14512211501 is a deficient number, since it is larger than the sum of its proper divisors (1).

14512211501 is an equidigital number, since it uses as much as digits as its factorization.

14512211501 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 400, while the sum is 23.

The spelling of 14512211501 in words is "fourteen billion, five hundred twelve million, two hundred eleven thousand, five hundred one".