1454112000000 has 2016 divisors, whose sum is σ = 6288303883680. Its totient is φ = 331776000000.

The previous prime is 1454111999953. The next prime is 1454112000007. The reversal of 1454112000000 is 2114541.

1454112000000 is a `hidden beast` number, since 1 + 4 + 541 + 120 + 0 + 0 + 0 + 0 + 0 = 666.

It is a super-2 number, since 2×1454112000000² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1454112000007) by changing a digit.

It is a polite number, since it can be written in 167 ways as a sum of consecutive naturals, for example, 85535999992 + ... + 85536000008.

It is an arithmetic number, because the mean of its divisors is an integer number (3119198355).

Almost surely, 2^{1454112000000} is an apocalyptic number.

1454112000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1454112000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (3144151941840).

1454112000000 is an abundant number, since it is smaller than the sum of its proper divisors (4834191883680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1454112000000 is an frugal number, since it uses more digits than its factorization.

1454112000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 95 (or 38 counting only the distinct ones).

The product of its (nonzero) digits is 160, while the sum is 18.

Adding to 1454112000000 its reverse (2114541), we get a palindrome (1454114114541).

The spelling of 1454112000000 in words is "one trillion, four hundred fifty-four billion, one hundred twelve million", and thus it is an aban number.