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145872526781 is a prime number
BaseRepresentation
bin1000011111011010101…
…1100001110110111101
3111221112002220011001002
42013312223201312331
54342221331324111
6151002442300045
713352600006432
oct2076653416675
9457462804032
10145872526781
1156956269463
12243304b7625
13109a9418407
1470bb537b89
153bdb57963b
hex21f6ae1dbd

145872526781 has 2 divisors, whose sum is σ = 145872526782. Its totient is φ = 145872526780.

The previous prime is 145872526769. The next prime is 145872526783. The reversal of 145872526781 is 187625278541.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 113484765625 + 32387761156 = 336875^2 + 179966^2 .

It is a cyclic number.

It is not a de Polignac number, because 145872526781 - 226 = 145805417917 is a prime.

It is a super-2 number, since 2×1458725267812 (a number of 23 digits) contains 22 as substring.

Together with 145872526783, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (145872526783) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72936263390 + 72936263391.

It is an arithmetic number, because the mean of its divisors is an integer number (72936263391).

Almost surely, 2145872526781 is an apocalyptic number.

It is an amenable number.

145872526781 is a deficient number, since it is larger than the sum of its proper divisors (1).

145872526781 is an equidigital number, since it uses as much as digits as its factorization.

145872526781 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 7526400, while the sum is 56.

The spelling of 145872526781 in words is "one hundred forty-five billion, eight hundred seventy-two million, five hundred twenty-six thousand, seven hundred eighty-one".