14841131 has 2 divisors, whose sum is σ = 14841132. Its totient is φ = 14841130.

The previous prime is 14841091. The next prime is 14841133. The reversal of 14841131 is 13114841.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14841131 - 2⁶ = 14841067 is a prime.

It is a super-2 number, since 2×14841131² = 440518338718322, which contains 22 as substring.

Together with 14841133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 14841097 and 14841106.

It is not a weakly prime, because it can be changed into another prime (14841133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7420565 + 7420566.

It is an arithmetic number, because the mean of its divisors is an integer number (7420566).

Almost surely, 2^14841131 is an apocalyptic number.

14841131 is a deficient number, since it is larger than the sum of its proper divisors (1).

14841131 is an equidigital number, since it uses as much as digits as its factorization.

14841131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 384, while the sum is 23.

The square root of 14841131 is about 3852.4188505405. The cubic root of 14841131 is about 245.7474383691.

Adding to 14841131 its reverse (13114841), we get a palindrome (27955972).

The spelling of 14841131 in words is "fourteen million, eight hundred forty-one thousand, one hundred thirty-one".