150011010011 has 4 divisors (see below), whose sum is σ = 150015888000. Its totient is φ = 150006132024.

The previous prime is 150011009989. The next prime is 150011010053. The reversal of 150011010011 is 110010110051.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-150011010011 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 150011009974 and 150011010001.

It is not an unprimeable number, because it can be changed into a prime (150011010211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2392571 + ... + 2454468.

It is an arithmetic number, because the mean of its divisors is an integer number (37503972000).

Almost surely, 2^150011010011 is an apocalyptic number.

150011010011 is a deficient number, since it is larger than the sum of its proper divisors (4877989).

150011010011 is an equidigital number, since it uses as much as digits as its factorization.

150011010011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4877988.

The product of its (nonzero) digits is 5, while the sum is 11.

Adding to 150011010011 its reverse (110010110051), we get a palindrome (260021120062).

The spelling of 150011010011 in words is "one hundred fifty billion, eleven million, ten thousand, eleven".