Base | Representation |
---|---|
bin | 1000101110110101111… |
… | …0010111111000110101 |
3 | 112100012200000112200111 |
4 | 2023231132113320311 |
5 | 4424211320103141 |
6 | 152525352143021 |
7 | 13560314614063 |
oct | 2135536277065 |
9 | 470180015614 |
10 | 150013050421 |
11 | 58690502123 |
12 | 250a7097a71 |
13 | 111b919b5c0 |
14 | 73913cb033 |
15 | 3d7ed0b381 |
hex | 22ed797e35 |
150013050421 has 8 divisors (see below), whose sum is σ = 163218007064. Its totient is φ = 137046021120.
The previous prime is 150013050347. The next prime is 150013050497. The reversal of 150013050421 is 124050310051.
It is a happy number.
It can be written as a sum of positive squares in 4 ways, for example, as 11472766321 + 138540284100 = 107111^2 + 372210^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 150013050421 - 27 = 150013050293 is a prime.
It is a super-2 number, since 2×1500130504212 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 150013050392 and 150013050401.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (150013050521) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 59480520 + ... + 59483041.
It is an arithmetic number, because the mean of its divisors is an integer number (20402250883).
Almost surely, 2150013050421 is an apocalyptic number.
It is an amenable number.
150013050421 is a deficient number, since it is larger than the sum of its proper divisors (13204956643).
150013050421 is a wasteful number, since it uses less digits than its factorization.
150013050421 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 118963671.
The product of its (nonzero) digits is 600, while the sum is 22.
Adding to 150013050421 its reverse (124050310051), we get a palindrome (274063360472).
It can be divided in two parts, 1500130 and 50421, that added together give a palindrome (1550551).
The spelling of 150013050421 in words is "one hundred fifty billion, thirteen million, fifty thousand, four hundred twenty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •