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150013050421 = 1397118963561
BaseRepresentation
bin1000101110110101111…
…0010111111000110101
3112100012200000112200111
42023231132113320311
54424211320103141
6152525352143021
713560314614063
oct2135536277065
9470180015614
10150013050421
1158690502123
12250a7097a71
13111b919b5c0
1473913cb033
153d7ed0b381
hex22ed797e35

150013050421 has 8 divisors (see below), whose sum is σ = 163218007064. Its totient is φ = 137046021120.

The previous prime is 150013050347. The next prime is 150013050497. The reversal of 150013050421 is 124050310051.

It is a happy number.

It can be written as a sum of positive squares in 4 ways, for example, as 11472766321 + 138540284100 = 107111^2 + 372210^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 150013050421 - 27 = 150013050293 is a prime.

It is a super-2 number, since 2×1500130504212 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 150013050392 and 150013050401.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (150013050521) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 59480520 + ... + 59483041.

It is an arithmetic number, because the mean of its divisors is an integer number (20402250883).

Almost surely, 2150013050421 is an apocalyptic number.

It is an amenable number.

150013050421 is a deficient number, since it is larger than the sum of its proper divisors (13204956643).

150013050421 is a wasteful number, since it uses less digits than its factorization.

150013050421 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 118963671.

The product of its (nonzero) digits is 600, while the sum is 22.

Adding to 150013050421 its reverse (124050310051), we get a palindrome (274063360472).

It can be divided in two parts, 1500130 and 50421, that added together give a palindrome (1550551).

The spelling of 150013050421 in words is "one hundred fifty billion, thirteen million, fifty thousand, four hundred twenty-one".

Divisors: 1 13 97 1261 118963561 1546526293 11539465417 150013050421