Base | Representation |
---|---|
bin | 1000101110110111111… |
… | …0111110011101111111 |
3 | 112100020021002202110111 |
4 | 2023231332332131333 |
5 | 4424221012101210 |
6 | 152530255250451 |
7 | 13560450351301 |
oct | 2135576763577 |
9 | 470207082414 |
10 | 150021597055 |
11 | 5869530a360 |
12 | 250a9b19a27 |
13 | 111baba1795 |
14 | 73925b3971 |
15 | 3d8094888a |
hex | 22edfbe77f |
150021597055 has 8 divisors (see below), whose sum is σ = 196391908944. Its totient is φ = 109106616000.
The previous prime is 150021597041. The next prime is 150021597079. The reversal of 150021597055 is 550795120051.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 150021597055 - 225 = 149988042623 is a prime.
It is a super-3 number, since 3×1500215970553 (a number of 35 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 150021596999 and 150021597017.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1363832646 + ... + 1363832755.
It is an arithmetic number, because the mean of its divisors is an integer number (24548988618).
Almost surely, 2150021597055 is an apocalyptic number.
150021597055 is a deficient number, since it is larger than the sum of its proper divisors (46370311889).
150021597055 is a wasteful number, since it uses less digits than its factorization.
150021597055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2727665417.
The product of its (nonzero) digits is 78750, while the sum is 40.
The spelling of 150021597055 in words is "one hundred fifty billion, twenty-one million, five hundred ninety-seven thousand, fifty-five".
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