Base | Representation |
---|---|
bin | 11100001100110101… |
… | …11100111011010111 |
3 | 1110002010210111010222 |
4 | 32012122330323113 |
5 | 222001332123020 |
6 | 10542201104555 |
7 | 1044120563306 |
oct | 160632747327 |
9 | 43063714128 |
10 | 15140114135 |
11 | 646a221923 |
12 | 2b2648815b |
13 | 1573896323 |
14 | a38a9843d |
15 | 5d928eb25 |
hex | 3866bced7 |
15140114135 has 4 divisors (see below), whose sum is σ = 18168136968. Its totient is φ = 12112091304.
The previous prime is 15140114117. The next prime is 15140114141. The reversal of 15140114135 is 53141104151.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 15140114135 - 210 = 15140113111 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1514011409 + ... + 1514011418.
It is an arithmetic number, because the mean of its divisors is an integer number (4542034242).
Almost surely, 215140114135 is an apocalyptic number.
15140114135 is a deficient number, since it is larger than the sum of its proper divisors (3028022833).
15140114135 is an equidigital number, since it uses as much as digits as its factorization.
15140114135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3028022832.
The product of its (nonzero) digits is 1200, while the sum is 26.
Adding to 15140114135 its reverse (53141104151), we get a palindrome (68281218286).
The spelling of 15140114135 in words is "fifteen billion, one hundred forty million, one hundred fourteen thousand, one hundred thirty-five".
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