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152200535 = 530440107
BaseRepresentation
bin10010001001001…
…10010101010111
3101121101120212212
421010212111113
5302430404120
623034104035
73525453224
oct1104462527
9347346785
10152200535
1178a05573
1242b7b01b
13256bc6b6
14162dc94b
15d5666c5
hex9126557

152200535 has 4 divisors (see below), whose sum is σ = 182640648. Its totient is φ = 121760424.

The previous prime is 152200519. The next prime is 152200537. The reversal of 152200535 is 535002251.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 152200535 - 24 = 152200519 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 152200535.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (152200537) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15220049 + ... + 15220058.

It is an arithmetic number, because the mean of its divisors is an integer number (45660162).

Almost surely, 2152200535 is an apocalyptic number.

152200535 is a deficient number, since it is larger than the sum of its proper divisors (30440113).

152200535 is an equidigital number, since it uses as much as digits as its factorization.

152200535 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30440112.

The product of its (nonzero) digits is 1500, while the sum is 23.

The square root of 152200535 is about 12336.9580934686. The cubic root of 152200535 is about 533.9149230657.

Adding to 152200535 its reverse (535002251), we get a palindrome (687202786).

The spelling of 152200535 in words is "one hundred fifty-two million, two hundred thousand, five hundred thirty-five".

Divisors: 1 5 30440107 152200535