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15242117 = 111385647
BaseRepresentation
bin111010001001…
…001110000101
31001200101020212
4322021032011
512400221432
61302405205
7243361442
oct72111605
931611225
1015242117
1186706a0
125130805
133208907
14204a9c9
1515112b2
hexe89385

15242117 has 4 divisors (see below), whose sum is σ = 16627776. Its totient is φ = 13856460.

The previous prime is 15242093. The next prime is 15242137. The reversal of 15242117 is 71124251.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 15242117 - 28 = 15241861 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 15242092 and 15242101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15242137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 692813 + ... + 692834.

It is an arithmetic number, because the mean of its divisors is an integer number (4156944).

Almost surely, 215242117 is an apocalyptic number.

It is an amenable number.

15242117 is a deficient number, since it is larger than the sum of its proper divisors (1385659).

15242117 is a wasteful number, since it uses less digits than its factorization.

15242117 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1385658.

The product of its digits is 560, while the sum is 23.

The square root of 15242117 is about 3904.1153927618. The cubic root of 15242117 is about 247.9410467311.

Adding to 15242117 its reverse (71124251), we get a palindrome (86366368).

The spelling of 15242117 in words is "fifteen million, two hundred forty-two thousand, one hundred seventeen".

Divisors: 1 11 1385647 15242117