Base | Representation |
---|---|
bin | 10110010000111100101… |
… | …110100010010100110011 |
3 | 12102021021020002102011020 |
4 | 112100330232202110303 |
5 | 200031443430031210 |
6 | 3130515040350523 |
7 | 215353333346154 |
oct | 26207456422463 |
9 | 5367236072136 |
10 | 1530027189555 |
11 | 53a976508327 |
12 | 208643015443 |
13 | b138630b3a7 |
14 | 540a755192b |
15 | 29bed594770 |
hex | 1643cba2533 |
1530027189555 has 64 divisors (see below), whose sum is σ = 2582955067392. Its totient is φ = 771854054400.
The previous prime is 1530027189533. The next prime is 1530027189631. The reversal of 1530027189555 is 5559817200351.
It is not a de Polignac number, because 1530027189555 - 26 = 1530027189491 is a prime.
It is a super-3 number, since 3×15300271895553 (a number of 38 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1530027189498 and 1530027189507.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 28650759 + ... + 28704111.
It is an arithmetic number, because the mean of its divisors is an integer number (40358672928).
Almost surely, 21530027189555 is an apocalyptic number.
1530027189555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1530027189555 is a deficient number, since it is larger than the sum of its proper divisors (1052927877837).
1530027189555 is a wasteful number, since it uses less digits than its factorization.
1530027189555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54308.
The product of its (nonzero) digits is 1890000, while the sum is 51.
The spelling of 1530027189555 in words is "one trillion, five hundred thirty billion, twenty-seven million, one hundred eighty-nine thousand, five hundred fifty-five".
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