Base | Representation |
---|---|
bin | 1101111100111010001100… |
… | …0000111010100111001100 |
3 | 2000022111101101010210200210 |
4 | 3133032203000322213030 |
5 | 4002312422130442200 |
6 | 52343043330522420 |
7 | 3142166031166323 |
oct | 337164300724714 |
9 | 60274341123623 |
10 | 15340063140300 |
11 | 4984758801088 |
12 | 1879010136410 |
13 | 87373c20a062 |
14 | 3b066a73d0ba |
15 | 1b906c12d650 |
hex | df3a303a9cc |
15340063140300 has 72 divisors (see below), whose sum is σ = 44386544499472. Its totient is φ = 4090441248000.
The previous prime is 15340063140277. The next prime is 15340063140319. The reversal of 15340063140300 is 304136004351.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3588690 + ... + 6599910.
Almost surely, 215340063140300 is an apocalyptic number.
15340063140300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
15340063140300 is an abundant number, since it is smaller than the sum of its proper divisors (29046481359172).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
15340063140300 is a wasteful number, since it uses less digits than its factorization.
15340063140300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3028219 (or 3028212 counting only the distinct ones).
The product of its (nonzero) digits is 12960, while the sum is 30.
Adding to 15340063140300 its reverse (304136004351), we get a palindrome (15644199144651).
The spelling of 15340063140300 in words is "fifteen trillion, three hundred forty billion, sixty-three million, one hundred forty thousand, three hundred".
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