Base | Representation |
---|---|
bin | 1000111011100010001… |
… | …1001111110111010010 |
3 | 112200000002222202100120 |
4 | 2032320203033313102 |
5 | 10003201021244442 |
6 | 154251421131110 |
7 | 14040615234246 |
oct | 2167043176722 |
9 | 480002882316 |
10 | 153420103122 |
11 | 5a079715260 |
12 | 258980b9a96 |
13 | 1160ccc3610 |
14 | 75d5ab2426 |
15 | 3ecdea84ec |
hex | 23b88cfdd2 |
153420103122 has 64 divisors (see below), whose sum is σ = 364052949120. Its totient is φ = 42489792000.
The previous prime is 153420103121. The next prime is 153420103127. The reversal of 153420103122 is 221301024351.
It is a super-3 number, since 3×1534201031223 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 153420103092 and 153420103101.
It is not an unprimeable number, because it can be changed into a prime (153420103121) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 798547 + ... + 971862.
It is an arithmetic number, because the mean of its divisors is an integer number (5688327330).
Almost surely, 2153420103122 is an apocalyptic number.
153420103122 is an abundant number, since it is smaller than the sum of its proper divisors (210632845998).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
153420103122 is a wasteful number, since it uses less digits than its factorization.
153420103122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1770539.
The product of its (nonzero) digits is 1440, while the sum is 24.
Adding to 153420103122 its reverse (221301024351), we get a palindrome (374721127473).
The spelling of 153420103122 in words is "one hundred fifty-three billion, four hundred twenty million, one hundred three thousand, one hundred twenty-two".
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