Base | Representation |
---|---|
bin | 11101110010100000… |
… | …11111111011110000 |
3 | 1112021120200012000000 |
4 | 32321100133323300 |
5 | 230223202340302 |
6 | 11202545430000 |
7 | 1104215234001 |
oct | 167120377360 |
9 | 45246605000 |
10 | 15993011952 |
11 | 6867702655 |
12 | 312403b300 |
13 | 167b4aa5a8 |
14 | aba0731a8 |
15 | 6390b531c |
hex | 3b941fef0 |
15993011952 has 140 divisors (see below), whose sum is σ = 46660956960. Its totient is φ = 5307773184.
The previous prime is 15993011939. The next prime is 15993011989. The reversal of 15993011952 is 25911039951.
15993011952 is a `hidden beast` number, since 1 + 599 + 3 + 0 + 1 + 1 + 9 + 52 = 666.
It is a junction number, because it is equal to n+sod(n) for n = 15993011898 and 15993011907.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 27 ways as a sum of consecutive naturals, for example, 2784828 + ... + 2790564.
Almost surely, 215993011952 is an apocalyptic number.
15993011952 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 15993011952, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (23330478480).
15993011952 is an abundant number, since it is smaller than the sum of its proper divisors (30667945008).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
15993011952 is an equidigital number, since it uses as much as digits as its factorization.
15993011952 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6002 (or 5981 counting only the distinct ones).
The product of its (nonzero) digits is 109350, while the sum is 45.
The spelling of 15993011952 in words is "fifteen billion, nine hundred ninety-three million, eleven thousand, nine hundred fifty-two".
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