16133115000000 has 448 divisors, whose sum is σ = 53673832907136. Its totient is φ = 4276608000000.

The previous prime is 16133114999983. The next prime is 16133115000011. The reversal of 16133115000000 is 51133161.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2594996892 + ... + 2595003108.

Almost surely, 2^{16133115000000} is an apocalyptic number.

16133115000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 16133115000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (26836916453568).

16133115000000 is an abundant number, since it is smaller than the sum of its proper divisors (37540717907136).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

16133115000000 is an frugal number, since it uses more digits than its factorization.

16133115000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6440 (or 6400 counting only the distinct ones).

The product of its (nonzero) digits is 270, while the sum is 21.

Adding to 16133115000000 its reverse (51133161), we get a palindrome (16133166133161).

The spelling of 16133115000000 in words is "sixteen trillion, one hundred thirty-three billion, one hundred fifteen million", and thus it is an aban number.