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164001335 = 532800267
BaseRepresentation
bin10011100011001…
…11011000110111
3102102121010112112
421301213120313
5313441020320
624135041235
74030663001
oct1161473067
9372533475
10164001335
11846356a3
1246b1021b
1327c91b14
1417ad1371
15e5e7ec5
hex9c67637

164001335 has 4 divisors (see below), whose sum is σ = 196801608. Its totient is φ = 131201064.

The previous prime is 164001311. The next prime is 164001347. The reversal of 164001335 is 533100461.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-164001335 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 164001335.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16400129 + ... + 16400138.

It is an arithmetic number, because the mean of its divisors is an integer number (49200402).

Almost surely, 2164001335 is an apocalyptic number.

164001335 is a deficient number, since it is larger than the sum of its proper divisors (32800273).

164001335 is an equidigital number, since it uses as much as digits as its factorization.

164001335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 32800272.

The product of its (nonzero) digits is 1080, while the sum is 23.

The square root of 164001335 is about 12806.3005977527. The cubic root of 164001335 is about 547.3718527186.

Adding to 164001335 its reverse (533100461), we get a palindrome (697101796).

The spelling of 164001335 in words is "one hundred sixty-four million, one thousand, three hundred thirty-five".

Divisors: 1 5 32800267 164001335