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165335040000 = 21533541323
BaseRepresentation
bin1001100111111010111…
…1001000000000000000
3120210202111001021001000
42121332233020000000
510202101232240000
6203542011412000
714642104436454
oct2317657100000
9523674037030
10165335040000
1164133357729
1228062454000
131278b644320
1480062aa664
15447a025000
hex267ebc8000

165335040000 has 1280 divisors, whose sum is σ = 687897302400. Its totient is φ = 38928384000.

The previous prime is 165335039993. The next prime is 165335040007. The reversal of 165335040000 is 40533561.

165335040000 is a `hidden beast` number, since 1 + 653 + 3 + 5 + 0 + 4 + 0 + 0 + 0 + 0 = 666.

It is an interprime number because it is at equal distance from previous prime (165335039993) and next prime (165335040007).

It is a tau number, because it is divible by the number of its divisors (1280).

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (165335040007) by changing a digit.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 7188479989 + ... + 7188480011.

Almost surely, 2165335040000 is an apocalyptic number.

165335040000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 165335040000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (343948651200).

165335040000 is an abundant number, since it is smaller than the sum of its proper divisors (522562262400).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

165335040000 is an frugal number, since it uses more digits than its factorization.

165335040000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 95 (or 46 counting only the distinct ones).

The product of its (nonzero) digits is 5400, while the sum is 27.

Adding to 165335040000 its reverse (40533561), we get a palindrome (165375573561).

The spelling of 165335040000 in words is "one hundred sixty-five billion, three hundred thirty-five million, forty thousand".