Base | Representation |
---|---|
bin | 10000111010001111… |
… | …010110000111010111 |
3 | 1201212101112200000020 |
4 | 100322033112013113 |
5 | 244141141023310 |
6 | 12201410520223 |
7 | 1211642462631 |
oct | 207217260727 |
9 | 51771480006 |
10 | 18156970455 |
11 | 7778155708 |
12 | 3628896073 |
13 | 1934900100 |
14 | c4360ba51 |
15 | 714063170 |
hex | 43a3d61d7 |
18156970455 has 24 divisors (see below), whose sum is σ = 31457761488. Its totient is φ = 8938814976.
The previous prime is 18156970423. The next prime is 18156970471. The reversal of 18156970455 is 55407965181.
It is not a de Polignac number, because 18156970455 - 25 = 18156970423 is a prime.
It is a super-3 number, since 3×181569704553 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 18156970398 and 18156970407.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3578722 + ... + 3583791.
It is an arithmetic number, because the mean of its divisors is an integer number (1310740062).
Almost surely, 218156970455 is an apocalyptic number.
18156970455 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
18156970455 is a deficient number, since it is larger than the sum of its proper divisors (13300791033).
18156970455 is a wasteful number, since it uses less digits than its factorization.
18156970455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7162547 (or 7162534 counting only the distinct ones).
The product of its (nonzero) digits is 1512000, while the sum is 51.
The spelling of 18156970455 in words is "eighteen billion, one hundred fifty-six million, nine hundred seventy thousand, four hundred fifty-five".
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