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18441113 = 23997687
BaseRepresentation
bin100011001011…
…0001110011001
31021200220110012
41012112032121
514210103423
61455131305
7312514115
oct106261631
937626405
1018441113
11a456099
126213b35
133a88a02
142640745
151944078
hex1196399

18441113 has 4 divisors (see below), whose sum is σ = 18451200. Its totient is φ = 18431028.

The previous prime is 18441091. The next prime is 18441119. The reversal of 18441113 is 31114481.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 31114481 = 137227113.

It is a cyclic number.

It is not a de Polignac number, because 18441113 - 220 = 17392537 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (18441119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1445 + ... + 6242.

It is an arithmetic number, because the mean of its divisors is an integer number (4612800).

Almost surely, 218441113 is an apocalyptic number.

It is an amenable number.

18441113 is a deficient number, since it is larger than the sum of its proper divisors (10087).

18441113 is an equidigital number, since it uses as much as digits as its factorization.

18441113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10086.

The product of its digits is 384, while the sum is 23.

The square root of 18441113 is about 4294.3117027063. The cubic root of 18441113 is about 264.1977063950.

Adding to 18441113 its reverse (31114481), we get a palindrome (49555594).

The spelling of 18441113 in words is "eighteen million, four hundred forty-one thousand, one hundred thirteen".

Divisors: 1 2399 7687 18441113