Base | Representation |
---|---|
bin | 10010011100111001… |
… | …001010011101101110 |
3 | 1220010201221221211122 |
4 | 102130321022131232 |
5 | 311033344144300 |
6 | 13033534020542 |
7 | 1300651033226 |
oct | 223471123556 |
9 | 56121857748 |
10 | 19812099950 |
11 | 8447460a25 |
12 | 3a0b047752 |
13 | 1b39798c86 |
14 | d5d373086 |
15 | 7ae501c85 |
hex | 49ce4a76e |
19812099950 has 48 divisors (see below), whose sum is σ = 39390666336. Its totient is φ = 7395379200.
The previous prime is 19812099929. The next prime is 19812099953. The reversal of 19812099950 is 5999021891.
It is a junction number, because it is equal to n+sod(n) for n = 19812099892 and 19812099901.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (19812099953) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 162947 + ... + 257246.
It is an arithmetic number, because the mean of its divisors is an integer number (820638882).
Almost surely, 219812099950 is an apocalyptic number.
19812099950 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
19812099950 is a deficient number, since it is larger than the sum of its proper divisors (19578566386).
19812099950 is a wasteful number, since it uses less digits than its factorization.
19812099950 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 420269 (or 420264 counting only the distinct ones).
The product of its (nonzero) digits is 524880, while the sum is 53.
The spelling of 19812099950 in words is "nineteen billion, eight hundred twelve million, ninety-nine thousand, nine hundred fifty".
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