1981470 has 24 divisors (see below), whose sum is σ = 4774104. Its totient is φ = 526336.

The previous prime is 1981457. The next prime is 1981471. The reversal of 1981470 is 741891.

It is a super-3 number, since 3×1981470³ = 23339081408767569000, which contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1981471) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 7582 + ... + 7838.

It is an arithmetic number, because the mean of its divisors is an integer number (198921).

2^1981470 is an apocalyptic number.

1981470 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1981470 is an abundant number, since it is smaller than the sum of its proper divisors (2792634).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1981470 is an equidigital number, since it uses as much as digits as its factorization.

1981470 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 524 (or 267 counting only the distinct ones).

The product of its (nonzero) digits is 2016, while the sum is 30.

The square root of 1981470 is about 1407.6469727883. The cubic root of 1981470 is about 125.6017914602.

Multiplying 1981470 by its sum of digits (30), we get a square (59444100 = 7710²).

1981470 divided by its sum of digits (30) gives a square (66049 = 257²).

The spelling of 1981470 in words is "one million, nine hundred eighty-one thousand, four hundred seventy".