Base | Representation |
---|---|
bin | 1011100010010011000… |
… | …1010011010001001010 |
3 | 200221112212210102101200 |
4 | 2320210301103101022 |
5 | 11221340430234440 |
6 | 231013424525030 |
7 | 20214135046110 |
oct | 2704461232112 |
9 | 627485712350 |
10 | 198185399370 |
11 | 77060544962 |
12 | 324aba80776 |
13 | 158c53b94aa |
14 | 98410c7ab0 |
15 | 524ded4c30 |
hex | 2e24c5344a |
198185399370 has 48 divisors (see below), whose sum is σ = 588893760000. Its totient is φ = 45299519712.
The previous prime is 198185399327. The next prime is 198185399393. The reversal of 198185399370 is 73993581891.
198185399370 is a `hidden beast` number, since 1 + 9 + 8 + 1 + 8 + 539 + 93 + 7 + 0 = 666.
It is a Harshad number since it is a multiple of its sum of digits (63).
It is a junction number, because it is equal to n+sod(n) for n = 198185399298 and 198185399307.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 157289370 + ... + 157290629.
It is an arithmetic number, because the mean of its divisors is an integer number (12268620000).
Almost surely, 2198185399370 is an apocalyptic number.
198185399370 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
198185399370 is an abundant number, since it is smaller than the sum of its proper divisors (390708360630).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
198185399370 is a wasteful number, since it uses less digits than its factorization.
198185399370 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 314580019 (or 314580016 counting only the distinct ones).
The product of its (nonzero) digits is 14696640, while the sum is 63.
The spelling of 198185399370 in words is "one hundred ninety-eight billion, one hundred eighty-five million, three hundred ninety-nine thousand, three hundred seventy".
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