Base | Representation |
---|---|
bin | 1011100010110001010… |
… | …1101001111101010000 |
3 | 200221212201201012100121 |
4 | 2320230111221331100 |
5 | 11222120431320000 |
6 | 231034202200024 |
7 | 20220236221633 |
oct | 2705425517520 |
9 | 627781635317 |
10 | 198312370000 |
11 | 77116187868 |
12 | 325264b3014 |
13 | 159157b4144 |
14 | 9853cd9c1a |
15 | 525a215b1a |
hex | 2e2c569f50 |
198312370000 has 50 divisors (see below), whose sum is σ = 480134103218. Its totient is φ = 79324944000.
The previous prime is 198312369977. The next prime is 198312370001. The reversal of 198312370000 is 73213891.
198312370000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 5 ways, for example, as 20505094416 + 177807275584 = 143196^2 + 421672^2 .
It is a tau number, because it is divible by the number of its divisors (50).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (198312370001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 9905619 + ... + 9925618.
Almost surely, 2198312370000 is an apocalyptic number.
198312370000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
198312370000 is an abundant number, since it is smaller than the sum of its proper divisors (281821733218).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
198312370000 is an equidigital number, since it uses as much as digits as its factorization.
198312370000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19831265 (or 19831244 counting only the distinct ones).
The product of its (nonzero) digits is 9072, while the sum is 34.
Adding to 198312370000 its reverse (73213891), we get a palindrome (198385583891).
The spelling of 198312370000 in words is "one hundred ninety-eight billion, three hundred twelve million, three hundred seventy thousand".
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