Base | Representation |
---|---|
bin | 10010100100010000… |
… | …000110000100111101 |
3 | 1220110100020221221120 |
4 | 102210100012010331 |
5 | 311312000124210 |
6 | 13054104021153 |
7 | 1304010252201 |
oct | 224420060475 |
9 | 56410227846 |
10 | 19935551805 |
11 | 8500110154 |
12 | 3a444617b9 |
13 | 1b59231100 |
14 | d7190ab01 |
15 | 7ba28a270 |
hex | 4a440613d |
19935551805 has 24 divisors (see below), whose sum is σ = 34539232608. Its totient is φ = 9814424256.
The previous prime is 19935551791. The next prime is 19935551807. The reversal of 19935551805 is 50815553991.
It is not a de Polignac number, because 19935551805 - 213 = 19935543613 is a prime.
It is a super-3 number, since 3×199355518053 (a number of 32 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (19935551807) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3929527 + ... + 3934596.
It is an arithmetic number, because the mean of its divisors is an integer number (1439134692).
Almost surely, 219935551805 is an apocalyptic number.
19935551805 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
19935551805 is a deficient number, since it is larger than the sum of its proper divisors (14603680803).
19935551805 is a wasteful number, since it uses less digits than its factorization.
19935551805 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7864157 (or 7864144 counting only the distinct ones).
The product of its (nonzero) digits is 1215000, while the sum is 51.
The spelling of 19935551805 in words is "nineteen billion, nine hundred thirty-five million, five hundred fifty-one thousand, eight hundred five".
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