Base | Representation |
---|---|
bin | 10010101000000110… |
… | …010111101010000011 |
3 | 1220121211201220211120 |
4 | 102220012113222003 |
5 | 311430012024420 |
6 | 13104331443323 |
7 | 1305423066126 |
oct | 225006275203 |
9 | 56554656746 |
10 | 20000111235 |
11 | 85335a5655 |
12 | 3a61bb6543 |
13 | 1b69716460 |
14 | d7a3143bd |
15 | 7c0c8dd40 |
hex | 4a8197a83 |
20000111235 has 64 divisors (see below), whose sum is σ = 35097753600. Its totient is φ = 9665929728.
The previous prime is 20000111221. The next prime is 20000111237. The reversal of 20000111235 is 53211100002.
It is not a de Polignac number, because 20000111235 - 29 = 20000110723 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is not an unprimeable number, because it can be changed into a prime (20000111237) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2753869 + ... + 2761121.
It is an arithmetic number, because the mean of its divisors is an integer number (548402400).
Almost surely, 220000111235 is an apocalyptic number.
20000111235 is a deficient number, since it is larger than the sum of its proper divisors (15097642365).
20000111235 is a wasteful number, since it uses less digits than its factorization.
20000111235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7532.
The product of its (nonzero) digits is 60, while the sum is 15.
Adding to 20000111235 its reverse (53211100002), we get a palindrome (73211211237).
The spelling of 20000111235 in words is "twenty billion, one hundred eleven thousand, two hundred thirty-five".
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