Base | Representation |
---|---|
bin | 101101011110011010011010… |
… | …000010011010110101101101 |
3 | 222020011000012110010110001101 |
4 | 231132122122002122311231 |
5 | 202203313130021243041 |
6 | 1545211355334043101 |
7 | 60061445533225111 |
oct | 5536323202326555 |
9 | 866130173113041 |
10 | 200002031431021 |
11 | 587aa426778566 |
12 | 1a5218977a9491 |
13 | 877a1590bc681 |
14 | 3756215741741 |
15 | 181c7a25aeb31 |
hex | b5e69a09ad6d |
200002031431021 has 2 divisors, whose sum is σ = 200002031431022. Its totient is φ = 200002031431020.
The previous prime is 200002031431019. The next prime is 200002031431051. The reversal of 200002031431021 is 120134130200002.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 136019854190025 + 63982177240996 = 11662755^2 + 7998886^2 .
It is a cyclic number.
It is not a de Polignac number, because 200002031431021 - 21 = 200002031431019 is a prime.
It is a super-4 number, since 4×2000020314310214 (a number of 58 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
Together with 200002031431019, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 200002031431021.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200002031431051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100001015715510 + 100001015715511.
It is an arithmetic number, because the mean of its divisors is an integer number (100001015715511).
Almost surely, 2200002031431021 is an apocalyptic number.
It is an amenable number.
200002031431021 is a deficient number, since it is larger than the sum of its proper divisors (1).
200002031431021 is an equidigital number, since it uses as much as digits as its factorization.
200002031431021 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 288, while the sum is 19.
Adding to 200002031431021 its reverse (120134130200002), we get a palindrome (320136161631023).
The spelling of 200002031431021 in words is "two hundred trillion, two billion, thirty-one million, four hundred thirty-one thousand, twenty-one".
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