Search a number
-
+
2000144411 = 11903168037
BaseRepresentation
bin111011100110111…
…1100100000011011
312011101121212022122
41313031330200123
513044014110121
6530250011455
7100364642546
oct16715744033
95141555278
102000144411
11937036111
12479a16b8b
1325b4c8005
1414d8d585d
15ba8e05ab
hex7737c81b

2000144411 has 4 divisors (see below), whose sum is σ = 2000324352. Its totient is φ = 1999964472.

The previous prime is 2000144407. The next prime is 2000144417. The reversal of 2000144411 is 1144410002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2000144411 - 22 = 2000144407 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2000144411.

It is not an unprimeable number, because it can be changed into a prime (2000144417) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 72116 + ... + 95921.

It is an arithmetic number, because the mean of its divisors is an integer number (500081088).

Almost surely, 22000144411 is an apocalyptic number.

2000144411 is a deficient number, since it is larger than the sum of its proper divisors (179941).

2000144411 is a wasteful number, since it uses less digits than its factorization.

2000144411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 179940.

The product of its (nonzero) digits is 128, while the sum is 17.

The square root of 2000144411 is about 44722.9740849152. The cubic root of 2000144411 is about 1259.9513735748.

Adding to 2000144411 its reverse (1144410002), we get a palindrome (3144554413).

The spelling of 2000144411 in words is "two billion, one hundred forty-four thousand, four hundred eleven".

Divisors: 1 11903 168037 2000144411