Base | Representation |
---|---|
bin | 1001000110001000101001… |
… | …10100111010000100000111 |
3 | 2121211011200121121100012111 |
4 | 10203010110310322010013 |
5 | 10110203110100023421 |
6 | 110312444132401451 |
7 | 4133045335465012 |
oct | 443042464720407 |
9 | 77734617540174 |
10 | 20002012111111 |
11 | 6411895426988 |
12 | 22b0635476287 |
13 | b2124910b824 |
14 | 4d216158a379 |
15 | 24a47183bee1 |
hex | 123114d3a107 |
20002012111111 has 2 divisors, whose sum is σ = 20002012111112. Its totient is φ = 20002012111110.
The previous prime is 20002012111097. The next prime is 20002012111181. The reversal of 20002012111111 is 11111121020002.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20002012111111 - 227 = 20001877893383 is a prime.
It is a super-2 number, since 2×200020121111112 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 20002012111091 and 20002012111100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20002012111181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10001006055555 + 10001006055556.
It is an arithmetic number, because the mean of its divisors is an integer number (10001006055556).
Almost surely, 220002012111111 is an apocalyptic number.
20002012111111 is a deficient number, since it is larger than the sum of its proper divisors (1).
20002012111111 is an equidigital number, since it uses as much as digits as its factorization.
20002012111111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 13.
Adding to 20002012111111 its reverse (11111121020002), we get a palindrome (31113133131113).
The spelling of 20002012111111 in words is "twenty trillion, two billion, twelve million, one hundred eleven thousand, one hundred eleven".
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