Base | Representation |
---|---|
bin | 1001000110011001011011… |
… | …10011111001010111110000 |
3 | 2121212000221110211001002012 |
4 | 10203030231303321113300 |
5 | 10110330032412223440 |
6 | 110320534120542052 |
7 | 4133514521536502 |
oct | 443145563712760 |
9 | 77760843731065 |
10 | 20011021211120 |
11 | 6415698873085 |
12 | 22b232a621928 |
13 | b22053726b34 |
14 | 4d2777c8dd72 |
15 | 24a7ec714e65 |
hex | 12332dcf95f0 |
20011021211120 has 80 divisors (see below), whose sum is σ = 46597431323520. Its totient is φ = 7992063110400.
The previous prime is 20011021211119. The next prime is 20011021211123. The reversal of 20011021211120 is 2111212011002.
It is a tau number, because it is divible by the number of its divisors (80).
It is a super-3 number, since 3×200110212111203 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 20011021211095 and 20011021211104.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20011021211123) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 153663635 + ... + 153793805.
It is an arithmetic number, because the mean of its divisors is an integer number (582467891544).
Almost surely, 220011021211120 is an apocalyptic number.
20011021211120 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
20011021211120 is an abundant number, since it is smaller than the sum of its proper divisors (26586410112400).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
20011021211120 is a wasteful number, since it uses less digits than its factorization.
20011021211120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 133134 (or 133128 counting only the distinct ones).
The product of its (nonzero) digits is 16, while the sum is 14.
Adding to 20011021211120 its reverse (2111212011002), we get a palindrome (22122233222122).
The spelling of 20011021211120 in words is "twenty trillion, eleven billion, twenty-one million, two hundred eleven thousand, one hundred twenty".
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