Base | Representation |
---|---|
bin | 11101000111101011011… |
… | …101010001001110100101 |
3 | 21002022012210201100011112 |
4 | 131013223131101032211 |
5 | 230241233142024031 |
6 | 4131144114314405 |
7 | 264401242202501 |
oct | 35075335211645 |
9 | 7068183640145 |
10 | 2001110111141 |
11 | 701736541809 |
12 | 2839b3888a05 |
13 | 11691c54537b |
14 | 6cbd60a1301 |
15 | 370c06ae62b |
hex | 1d1eb7513a5 |
2001110111141 has 2 divisors, whose sum is σ = 2001110111142. Its totient is φ = 2001110111140.
The previous prime is 2001110111107. The next prime is 2001110111197. The reversal of 2001110111141 is 1411110111002.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1972971390625 + 28138720516 = 1404625^2 + 167746^2 .
It is a cyclic number.
It is not a de Polignac number, because 2001110111141 - 222 = 2001105916837 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2001110101141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000555055570 + 1000555055571.
It is an arithmetic number, because the mean of its divisors is an integer number (1000555055571).
Almost surely, 22001110111141 is an apocalyptic number.
It is an amenable number.
2001110111141 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001110111141 is an equidigital number, since it uses as much as digits as its factorization.
2001110111141 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8, while the sum is 14.
Adding to 2001110111141 its reverse (1411110111002), we get a palindrome (3412220222143).
The spelling of 2001110111141 in words is "two trillion, one billion, one hundred ten million, one hundred eleven thousand, one hundred forty-one".
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