Base | Representation |
---|---|
bin | 1011101001011110001… |
… | …1010110011010111111 |
3 | 201010112002101021101011 |
4 | 2322113203112122333 |
5 | 11234311421401421 |
6 | 231532455500051 |
7 | 20312640321115 |
oct | 2722743263277 |
9 | 633462337334 |
10 | 200111122111 |
11 | 7795956995a |
12 | 32948987627 |
13 | 15b413581c4 |
14 | 9984b69ab5 |
15 | 53130c44e1 |
hex | 2e978d66bf |
200111122111 has 2 divisors, whose sum is σ = 200111122112. Its totient is φ = 200111122110.
The previous prime is 200111122093. The next prime is 200111122117. The reversal of 200111122111 is 111221111002.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200111122111 - 213 = 200111113919 is a prime.
It is a super-2 number, since 2×2001111221112 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 200111122091 and 200111122100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200111122117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100055561055 + 100055561056.
It is an arithmetic number, because the mean of its divisors is an integer number (100055561056).
Almost surely, 2200111122111 is an apocalyptic number.
200111122111 is a deficient number, since it is larger than the sum of its proper divisors (1).
200111122111 is an equidigital number, since it uses as much as digits as its factorization.
200111122111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 13.
Adding to 200111122111 its reverse (111221111002), we get a palindrome (311332233113).
The spelling of 200111122111 in words is "two hundred billion, one hundred eleven million, one hundred twenty-two thousand, one hundred eleven".
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