Base | Representation |
---|---|
bin | 101101100000001000011000… |
… | …101110011000010100011111 |
3 | 222020120022000022111011120112 |
4 | 231200020120232120110133 |
5 | 202212232001434014442 |
6 | 1545341525303240235 |
7 | 60103126104061316 |
oct | 5540103056302437 |
9 | 866508008434515 |
10 | 200120121001247 |
11 | 588455152034a7 |
12 | 1a54075374907b |
13 | 8788328560b05 |
14 | 375bc1906727d |
15 | 18208b4997082 |
hex | b60218b9851f |
200120121001247 has 2 divisors, whose sum is σ = 200120121001248. Its totient is φ = 200120121001246.
The previous prime is 200120121001181. The next prime is 200120121001249. The reversal of 200120121001247 is 742100121021002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200120121001247 - 216 = 200120120935711 is a prime.
Together with 200120121001249, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200120121001249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100060060500623 + 100060060500624.
It is an arithmetic number, because the mean of its divisors is an integer number (100060060500624).
Almost surely, 2200120121001247 is an apocalyptic number.
200120121001247 is a deficient number, since it is larger than the sum of its proper divisors (1).
200120121001247 is an equidigital number, since it uses as much as digits as its factorization.
200120121001247 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 448, while the sum is 23.
Adding to 200120121001247 its reverse (742100121021002), we get a palindrome (942220242022249).
The spelling of 200120121001247 in words is "two hundred trillion, one hundred twenty billion, one hundred twenty-one million, one thousand, two hundred forty-seven".
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