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2001210012112 = 24539923166443
BaseRepresentation
bin11101000111110001011…
…010010111000111010000
321002022110202200211112111
4131013301122113013100
5230241434230341422
64131202043435104
7264403564303123
oct35076132270720
97068422624474
102001210012112
117017879758a3
12283a21225a94
13116937152a7c
146cc054683ba
15370c9344a77
hex1d1f16971d0

2001210012112 has 20 divisors (see below), whose sum is σ = 3878062725600. Its totient is φ = 1000419631328.

The previous prime is 2001210012101. The next prime is 2001210012127. The reversal of 2001210012112 is 2112100121002.

It is a super-2 number, since 2×20012100121122 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2001210012092 and 2001210012101.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11496838 + ... + 11669605.

It is an arithmetic number, because the mean of its divisors is an integer number (193903136280).

Almost surely, 22001210012112 is an apocalyptic number.

It is an amenable number.

2001210012112 is a deficient number, since it is larger than the sum of its proper divisors (1876852713488).

2001210012112 is a wasteful number, since it uses less digits than its factorization.

2001210012112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23171850 (or 23171844 counting only the distinct ones).

The product of its (nonzero) digits is 16, while the sum is 13.

Adding to 2001210012112 its reverse (2112100121002), we get a palindrome (4113310133114).

The spelling of 2001210012112 in words is "two trillion, one billion, two hundred ten million, twelve thousand, one hundred twelve".

Divisors: 1 2 4 8 16 5399 10798 21596 43192 86384 23166443 46332886 92665772 185331544 370663088 125075625757 250151251514 500302503028 1000605006056 2001210012112