Base | Representation |
---|---|
bin | 10010101000111100… |
… | …100111010110100100 |
3 | 1220122211111101002122 |
4 | 102220330213112210 |
5 | 311442132100200 |
6 | 13110000325112 |
7 | 1305655003055 |
oct | 225074472644 |
9 | 56584441078 |
10 | 20014331300 |
11 | 8540628377 |
12 | 3a66913798 |
13 | 1b6c654ab2 |
14 | d7c17672c |
15 | 7c214c385 |
hex | 4a8f275a4 |
20014331300 has 36 divisors (see below), whose sum is σ = 43494101616. Its totient is φ = 7994119200.
The previous prime is 20014331299. The next prime is 20014331369. The reversal of 20014331300 is 313341002.
It is a happy number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 75722 + ... + 213921.
Almost surely, 220014331300 is an apocalyptic number.
20014331300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
20014331300 is an abundant number, since it is smaller than the sum of its proper divisors (23479770316).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
20014331300 is a wasteful number, since it uses less digits than its factorization.
20014331300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 290348 (or 290341 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 17.
Adding to 20014331300 its reverse (313341002), we get a palindrome (20327672302).
The spelling of 20014331300 in words is "twenty billion, fourteen million, three hundred thirty-one thousand, three hundred".
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