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2002312111300 = 225297836324683
BaseRepresentation
bin11101001000110011000…
…110100010010011000100
321002102022120111021101221
4131020303012202103010
5230301213400030200
64131503253330124
7264443106061234
oct35106306422304
97072276437357
102002312111300
117021a2a94276
1228408a336944
13116a8158a077
146ccab991cc4
1537140e9291a
hex1d2331a24c4

2002312111300 has 72 divisors (see below), whose sum is σ = 4390514051616. Its totient is φ = 792540994560.

The previous prime is 2002312111279. The next prime is 2002312111321. The reversal of 2002312111300 is 31112132002.

It is an interprime number because it is at equal distance from previous prime (2002312111279) and next prime (2002312111321).

It is a super-3 number, since 3×20023121113003 (a number of 38 digits) contains 333 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 81108759 + ... + 81133441.

It is an arithmetic number, because the mean of its divisors is an integer number (60979361828).

Almost surely, 22002312111300 is an apocalyptic number.

2002312111300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 2002312111300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2195257025808).

2002312111300 is an abundant number, since it is smaller than the sum of its proper divisors (2388201940316).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2002312111300 is a wasteful number, since it uses less digits than its factorization.

2002312111300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33157 (or 33150 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 2002312111300 its reverse (31112132002), we get a palindrome (2033424243302).

The spelling of 2002312111300 in words is "two trillion, two billion, three hundred twelve million, one hundred eleven thousand, three hundred".

Divisors: 1 2 4 5 10 20 25 50 97 100 194 388 485 970 1940 2425 4850 8363 9700 16726 24683 33452 41815 49366 83630 98732 123415 167260 209075 246830 418150 493660 617075 811211 836300 1234150 1622422 2394251 2468300 3244844 4056055 4788502 8112110 9577004 11971255 16224220 20280275 23942510 40560550 47885020 59856275 81121100 119712550 206423929 239425100 412847858 825695716 1032119645 2064239290 4128478580 5160598225 10321196450 20023121113 20642392900 40046242226 80092484452 100115605565 200231211130 400462422260 500578027825 1001156055650 2002312111300