Base | Representation |
---|---|
bin | 11101001000110011001… |
… | …001111011010001101000 |
3 | 21002102022122011102112020 |
4 | 131020303021323101220 |
5 | 230301214112000130 |
6 | 4131503324344440 |
7 | 264443116452303 |
oct | 35106311732150 |
9 | 7072278142466 |
10 | 2002313000040 |
11 | 7021a3540a71 |
12 | 28408a6a5120 |
13 | 116a8180b752 |
14 | 6ccabb43b3a |
15 | 371410bae10 |
hex | 1d23327b468 |
2002313000040 has 64 divisors (see below), whose sum is σ = 6153449722560. Its totient is φ = 520926958080.
The previous prime is 2002312999997. The next prime is 2002313000069. The reversal of 2002313000040 is 400003132002.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a junction number, because it is equal to n+sod(n) for n = 2002312999983 and 2002313000019.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 203482174 + ... + 203492013.
It is an arithmetic number, because the mean of its divisors is an integer number (96147651915).
Almost surely, 22002313000040 is an apocalyptic number.
2002313000040 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
2002313000040 is an abundant number, since it is smaller than the sum of its proper divisors (4151136722520).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2002313000040 is a wasteful number, since it uses less digits than its factorization.
2002313000040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 406974242 (or 406974238 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 15.
Adding to 2002313000040 its reverse (400003132002), we get a palindrome (2402316132042).
The spelling of 2002313000040 in words is "two trillion, two billion, three hundred thirteen million, forty", and thus it is an aban number.
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