200302011112013 has 4 divisors (see below), whose sum is σ = 202552595506620. Its totient is φ = 198051426717408.

The previous prime is 200302011111973. The next prime is 200302011112039. The reversal of 200302011112013 is 310211110203002.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 125741169352969 + 74560841759044 = 11213437^2 + 8634862^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-200302011112013 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200302011111982 and 200302011112000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200302011112213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1125292197170 + ... + 1125292197347.

It is an arithmetic number, because the mean of its divisors is an integer number (50638148876655).

Almost surely, 2^{200302011112013} is an apocalyptic number.

It is an amenable number.

200302011112013 is a deficient number, since it is larger than the sum of its proper divisors (2250584394607).

200302011112013 is an equidigital number, since it uses as much as digits as its factorization.

200302011112013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2250584394606.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 200302011112013 its reverse (310211110203002), we get a palindrome (510513121315015).

The spelling of 200302011112013 in words is "two hundred trillion, three hundred two billion, eleven million, one hundred twelve thousand, thirteen".