Base | Representation |
---|---|
bin | 10010101001111100… |
… | …101111110110011101 |
3 | 1220201000010111212020 |
4 | 102221330233312131 |
5 | 312010433041300 |
6 | 13111400530353 |
7 | 1306250623524 |
oct | 225174576635 |
9 | 56630114766 |
10 | 20031143325 |
11 | 854a070506 |
12 | 3a704809b9 |
13 | 1b72c9013b |
14 | d804b14bb |
15 | 7c386d8a0 |
hex | 4a9f2fd9d |
20031143325 has 48 divisors (see below), whose sum is σ = 34810736256. Its totient is φ = 10144076800.
The previous prime is 20031143323. The next prime is 20031143347. The reversal of 20031143325 is 52334113002.
It is not a de Polignac number, because 20031143325 - 21 = 20031143323 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 20031143295 and 20031143304.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20031143323) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 193945 + ... + 278705.
It is an arithmetic number, because the mean of its divisors is an integer number (725223672).
Almost surely, 220031143325 is an apocalyptic number.
20031143325 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
It is an amenable number.
20031143325 is a deficient number, since it is larger than the sum of its proper divisors (14779592931).
20031143325 is a wasteful number, since it uses less digits than its factorization.
20031143325 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 84934 (or 84929 counting only the distinct ones).
The product of its (nonzero) digits is 2160, while the sum is 24.
Adding to 20031143325 its reverse (52334113002), we get a palindrome (72365256327).
The spelling of 20031143325 in words is "twenty billion, thirty-one million, one hundred forty-three thousand, three hundred twenty-five".
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