Search a number
-
+
2003425439 is a prime number
BaseRepresentation
bin111011101101001…
…1101100010011111
312011121210120001012
41313122131202133
513100334103224
6530444205435
7100434556331
oct16732354237
95147716035
102003425439
11938977204
1247ab3987b
1325c0a6552
1415010b451
15bad3c80e
hex7769d89f

2003425439 has 2 divisors, whose sum is σ = 2003425440. Its totient is φ = 2003425438.

The previous prime is 2003425423. The next prime is 2003425441. The reversal of 2003425439 is 9345243002.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2003425439 - 24 = 2003425423 is a prime.

Together with 2003425441, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2003425139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001712719 + 1001712720.

It is an arithmetic number, because the mean of its divisors is an integer number (1001712720).

Almost surely, 22003425439 is an apocalyptic number.

2003425439 is a deficient number, since it is larger than the sum of its proper divisors (1).

2003425439 is an equidigital number, since it uses as much as digits as its factorization.

2003425439 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25920, while the sum is 32.

The square root of 2003425439 is about 44759.6407380578. The cubic root of 2003425439 is about 1260.6399367506.

The spelling of 2003425439 in words is "two billion, three million, four hundred twenty-five thousand, four hundred thirty-nine".