Base | Representation |
---|---|
bin | 111011101101001… |
… | …1101100010100001 |
3 | 12011121210120001021 |
4 | 1313122131202201 |
5 | 13100334103231 |
6 | 530444205441 |
7 | 100434556333 |
oct | 16732354241 |
9 | 5147716037 |
10 | 2003425441 |
11 | 938977206 |
12 | 47ab39881 |
13 | 25c0a6554 |
14 | 15010b453 |
15 | bad3c811 |
hex | 7769d8a1 |
2003425441 has 2 divisors, whose sum is σ = 2003425442. Its totient is φ = 2003425440.
The previous prime is 2003425439. The next prime is 2003425451. The reversal of 2003425441 is 1445243002.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1401753600 + 601671841 = 37440^2 + 24529^2 .
It is a cyclic number.
It is not a de Polignac number, because 2003425441 - 21 = 2003425439 is a prime.
Together with 2003425439, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (2003425451) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001712720 + 1001712721.
It is an arithmetic number, because the mean of its divisors is an integer number (1001712721).
Almost surely, 22003425441 is an apocalyptic number.
It is an amenable number.
2003425441 is a deficient number, since it is larger than the sum of its proper divisors (1).
2003425441 is an equidigital number, since it uses as much as digits as its factorization.
2003425441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3840, while the sum is 25.
The square root of 2003425441 is about 44759.6407603993. The cubic root of 2003425441 is about 1260.6399371701.
Adding to 2003425441 its reverse (1445243002), we get a palindrome (3448668443).
The spelling of 2003425441 in words is "two billion, three million, four hundred twenty-five thousand, four hundred forty-one".
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