Base | Representation |
---|---|
bin | 101101100011011000001111… |
… | …111001001000011111011000 |
3 | 222021100122002211002011122112 |
4 | 231203120033321020133120 |
5 | 202224411100121440230 |
6 | 1550032240242211452 |
7 | 60125220004605041 |
oct | 5543301771103730 |
9 | 867318084064575 |
10 | 200343311124440 |
11 | 58921137210470 |
12 | 1a577a61653b88 |
13 | 87a33a7148973 |
14 | 376894cda78c8 |
15 | 18265c8c83d95 |
hex | b6360fe487d8 |
200343311124440 has 32 divisors (see below), whose sum is σ = 491751763670160. Its totient is φ = 72852113136000.
The previous prime is 200343311124431. The next prime is 200343311124553. The reversal of 200343311124440 is 44421113343002.
It is a junction number, because it is equal to n+sod(n) for n = 200343311124397 and 200343311124406.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 227662853111 + ... + 227662853990.
Almost surely, 2200343311124440 is an apocalyptic number.
200343311124440 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
200343311124440 is an abundant number, since it is smaller than the sum of its proper divisors (291408452545720).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
200343311124440 is a wasteful number, since it uses less digits than its factorization.
200343311124440 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 455325707123 (or 455325707119 counting only the distinct ones).
The product of its (nonzero) digits is 27648, while the sum is 32.
Adding to 200343311124440 its reverse (44421113343002), we get a palindrome (244764424467442).
The spelling of 200343311124440 in words is "two hundred trillion, three hundred forty-three billion, three hundred eleven million, one hundred twenty-four thousand, four hundred forty".
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