Base | Representation |
---|---|
bin | 100110010110… |
… | …1111111001110 |
3 | 1101211202112100 |
4 | 1030231333032 |
5 | 20122030220 |
6 | 1555015530 |
7 | 332641362 |
oct | 114557716 |
9 | 41752470 |
10 | 20111310 |
11 | 10396a1a |
12 | 689a5a6 |
13 | 4221cab |
14 | 29572a2 |
15 | 1b73d90 |
hex | 132dfce |
20111310 has 72 divisors (see below), whose sum is σ = 55275480. Its totient is φ = 5072544.
The previous prime is 20111303. The next prime is 20111317. The reversal of 20111310 is 1311102.
It is an interprime number because it is at equal distance from previous prime (20111303) and next prime (20111317).
It is a super-2 number, since 2×201113102 = 808929579832200, which contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (9).
It is a junction number, because it is equal to n+sod(n) for n = 20111292 and 20111301.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20111317) by changing a digit.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 32181 + ... + 32799.
It is an arithmetic number, because the mean of its divisors is an integer number (767715).
Almost surely, 220111310 is an apocalyptic number.
It is a practical number, because each smaller number is the sum of distinct divisors of 20111310, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (27637740).
20111310 is an abundant number, since it is smaller than the sum of its proper divisors (35164170).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
20111310 is a wasteful number, since it uses less digits than its factorization.
20111310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 670 (or 648 counting only the distinct ones).
The product of its (nonzero) digits is 6, while the sum is 9.
The square root of 20111310 is about 4484.5635239118. The cubic root of 20111310 is about 271.9444000398.
Adding to 20111310 its reverse (1311102), we get a palindrome (21422412).
It can be divided in two parts, 2011 and 1310, that added together give a triangular number (3321 = T81).
The spelling of 20111310 in words is "twenty million, one hundred eleven thousand, three hundred ten".
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