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20111310 = 2325192619
BaseRepresentation
bin100110010110…
…1111111001110
31101211202112100
41030231333032
520122030220
61555015530
7332641362
oct114557716
941752470
1020111310
1110396a1a
12689a5a6
134221cab
1429572a2
151b73d90
hex132dfce

20111310 has 72 divisors (see below), whose sum is σ = 55275480. Its totient is φ = 5072544.

The previous prime is 20111303. The next prime is 20111317. The reversal of 20111310 is 1311102.

It is an interprime number because it is at equal distance from previous prime (20111303) and next prime (20111317).

It is a super-2 number, since 2×201113102 = 808929579832200, which contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (9).

It is a junction number, because it is equal to n+sod(n) for n = 20111292 and 20111301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20111317) by changing a digit.

It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 32181 + ... + 32799.

It is an arithmetic number, because the mean of its divisors is an integer number (767715).

Almost surely, 220111310 is an apocalyptic number.

It is a practical number, because each smaller number is the sum of distinct divisors of 20111310, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (27637740).

20111310 is an abundant number, since it is smaller than the sum of its proper divisors (35164170).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

20111310 is a wasteful number, since it uses less digits than its factorization.

20111310 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 670 (or 648 counting only the distinct ones).

The product of its (nonzero) digits is 6, while the sum is 9.

The square root of 20111310 is about 4484.5635239118. The cubic root of 20111310 is about 271.9444000398.

Adding to 20111310 its reverse (1311102), we get a palindrome (21422412).

It can be divided in two parts, 2011 and 1310, that added together give a triangular number (3321 = T81).

The spelling of 20111310 in words is "twenty million, one hundred eleven thousand, three hundred ten".

Divisors: 1 2 3 5 6 9 10 15 18 19 30 38 45 57 90 95 114 171 190 285 342 361 570 619 722 855 1083 1238 1710 1805 1857 2166 3095 3249 3610 3714 5415 5571 6190 6498 9285 10830 11142 11761 16245 18570 23522 27855 32490 35283 55710 58805 70566 105849 117610 176415 211698 223459 352830 446918 529245 670377 1058490 1117295 1340754 2011131 2234590 3351885 4022262 6703770 10055655 20111310