20120011111111 has 2 divisors, whose sum is σ = 20120011111112. Its totient is φ = 20120011111110.

The previous prime is 20120011111073. The next prime is 20120011111117. The reversal of 20120011111111 is 11111111002102.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 20120011111111 - 2¹⁷ = 20120010980039 is a prime.

It is a super-2 number, since 2×20120011111111² (a number of 27 digits) contains 22 as substring.

20120011111111 is a modest number, since divided by 11111111 gives 201200 as remainder.

It is a junction number, because it is equal to n+sod(n) for n = 20120011111091 and 20120011111100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20120011111117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10060005555555 + 10060005555556.

It is an arithmetic number, because the mean of its divisors is an integer number (10060005555556).

Almost surely, 2^{20120011111111} is an apocalyptic number.

20120011111111 is a deficient number, since it is larger than the sum of its proper divisors (1).

20120011111111 is an equidigital number, since it uses as much as digits as its factorization.

20120011111111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4, while the sum is 13.

Adding to 20120011111111 its reverse (11111111002102), we get a palindrome (31231122113213).

The spelling of 20120011111111 in words is "twenty trillion, one hundred twenty billion, eleven million, one hundred eleven thousand, one hundred eleven".