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201211112102000 = 245371113990110151
BaseRepresentation
bin101101110000000000011100…
…110111001001100001110000
3222101102121001100201102211012
4231300000130313021201300
5202333120324144231000
61551535035301010052
760245010634321430
oct5560003467114160
9871377040642735
10201211112102000
1159126176245110
121a69808a3b3928
138837184a91270
143798953c802c0
15183de695ae735
hexb7001cdc9870

201211112102000 has 640 divisors, whose sum is σ = 653371357556736. Its totient is φ = 57879360000000.

The previous prime is 201211112101969. The next prime is 201211112102023. The reversal of 201211112102000 is 201211112102.

It is a super-2 number, since 2×2012111121020002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (14).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 19821796925 + ... + 19821807075.

Almost surely, 2201211112102000 is an apocalyptic number.

201211112102000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 201211112102000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (326685678778368).

201211112102000 is an abundant number, since it is smaller than the sum of its proper divisors (452160245454736).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

201211112102000 is a wasteful number, since it uses less digits than its factorization.

201211112102000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20106 (or 20090 counting only the distinct ones).

The product of its (nonzero) digits is 16, while the sum is 14.

Adding to 201211112102000 its reverse (201211112102), we get a palindrome (201412323214102).

201211112102000 divided by its reverse (201211112102) gives a cube (1000 = 103).

It can be divided in two parts, 201211 and 112102000, that added together give a palindrome (112303211).

The spelling of 201211112102000 in words is "two hundred one trillion, two hundred eleven billion, one hundred twelve million, one hundred two thousand".