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201220001111 is a prime number
BaseRepresentation
bin1011101101100110100…
…1011000110101010111
3201020101100221011101202
42323121221120311113
511244044310013421
6232234510543115
720352263534363
oct2733151306527
9636340834352
10201220001111
1178378499088
1232bb8207a9b
1315c89cc741c
149a4c13a2a3
15537a61110b
hex2ed9a58d57

201220001111 has 2 divisors, whose sum is σ = 201220001112. Its totient is φ = 201220001110.

The previous prime is 201220001071. The next prime is 201220001113. The reversal of 201220001111 is 111100022102.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-201220001111 is a prime.

It is a super-2 number, since 2×2012200011112 (a number of 23 digits) contains 22 as substring.

Together with 201220001113, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 201220001092 and 201220001101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201220001113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100610000555 + 100610000556.

It is an arithmetic number, because the mean of its divisors is an integer number (100610000556).

Almost surely, 2201220001111 is an apocalyptic number.

201220001111 is a deficient number, since it is larger than the sum of its proper divisors (1).

201220001111 is an equidigital number, since it uses as much as digits as its factorization.

201220001111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8, while the sum is 11.

Adding to 201220001111 its reverse (111100022102), we get a palindrome (312320023213).

The spelling of 201220001111 in words is "two hundred one billion, two hundred twenty million, one thousand, one hundred eleven".